Integrand size = 18, antiderivative size = 169 \[ \int \frac {A+B x}{x^{7/2} (a+b x)^3} \, dx=-\frac {7 (9 A b-5 a B)}{20 a^3 b x^{5/2}}+\frac {7 (9 A b-5 a B)}{12 a^4 x^{3/2}}-\frac {7 b (9 A b-5 a B)}{4 a^5 \sqrt {x}}+\frac {A b-a B}{2 a b x^{5/2} (a+b x)^2}+\frac {9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}-\frac {7 b^{3/2} (9 A b-5 a B) \arctan \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{4 a^{11/2}} \]
[Out]
Time = 0.05 (sec) , antiderivative size = 169, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.278, Rules used = {79, 44, 53, 65, 211} \[ \int \frac {A+B x}{x^{7/2} (a+b x)^3} \, dx=-\frac {7 b^{3/2} (9 A b-5 a B) \arctan \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{4 a^{11/2}}-\frac {7 b (9 A b-5 a B)}{4 a^5 \sqrt {x}}+\frac {7 (9 A b-5 a B)}{12 a^4 x^{3/2}}-\frac {7 (9 A b-5 a B)}{20 a^3 b x^{5/2}}+\frac {9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}+\frac {A b-a B}{2 a b x^{5/2} (a+b x)^2} \]
[In]
[Out]
Rule 44
Rule 53
Rule 65
Rule 79
Rule 211
Rubi steps \begin{align*} \text {integral}& = \frac {A b-a B}{2 a b x^{5/2} (a+b x)^2}-\frac {\left (-\frac {9 A b}{2}+\frac {5 a B}{2}\right ) \int \frac {1}{x^{7/2} (a+b x)^2} \, dx}{2 a b} \\ & = \frac {A b-a B}{2 a b x^{5/2} (a+b x)^2}+\frac {9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}+\frac {(7 (9 A b-5 a B)) \int \frac {1}{x^{7/2} (a+b x)} \, dx}{8 a^2 b} \\ & = -\frac {7 (9 A b-5 a B)}{20 a^3 b x^{5/2}}+\frac {A b-a B}{2 a b x^{5/2} (a+b x)^2}+\frac {9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}-\frac {(7 (9 A b-5 a B)) \int \frac {1}{x^{5/2} (a+b x)} \, dx}{8 a^3} \\ & = -\frac {7 (9 A b-5 a B)}{20 a^3 b x^{5/2}}+\frac {7 (9 A b-5 a B)}{12 a^4 x^{3/2}}+\frac {A b-a B}{2 a b x^{5/2} (a+b x)^2}+\frac {9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}+\frac {(7 b (9 A b-5 a B)) \int \frac {1}{x^{3/2} (a+b x)} \, dx}{8 a^4} \\ & = -\frac {7 (9 A b-5 a B)}{20 a^3 b x^{5/2}}+\frac {7 (9 A b-5 a B)}{12 a^4 x^{3/2}}-\frac {7 b (9 A b-5 a B)}{4 a^5 \sqrt {x}}+\frac {A b-a B}{2 a b x^{5/2} (a+b x)^2}+\frac {9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}-\frac {\left (7 b^2 (9 A b-5 a B)\right ) \int \frac {1}{\sqrt {x} (a+b x)} \, dx}{8 a^5} \\ & = -\frac {7 (9 A b-5 a B)}{20 a^3 b x^{5/2}}+\frac {7 (9 A b-5 a B)}{12 a^4 x^{3/2}}-\frac {7 b (9 A b-5 a B)}{4 a^5 \sqrt {x}}+\frac {A b-a B}{2 a b x^{5/2} (a+b x)^2}+\frac {9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}-\frac {\left (7 b^2 (9 A b-5 a B)\right ) \text {Subst}\left (\int \frac {1}{a+b x^2} \, dx,x,\sqrt {x}\right )}{4 a^5} \\ & = -\frac {7 (9 A b-5 a B)}{20 a^3 b x^{5/2}}+\frac {7 (9 A b-5 a B)}{12 a^4 x^{3/2}}-\frac {7 b (9 A b-5 a B)}{4 a^5 \sqrt {x}}+\frac {A b-a B}{2 a b x^{5/2} (a+b x)^2}+\frac {9 A b-5 a B}{4 a^2 b x^{5/2} (a+b x)}-\frac {7 b^{3/2} (9 A b-5 a B) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{4 a^{11/2}} \\ \end{align*}
Time = 0.17 (sec) , antiderivative size = 133, normalized size of antiderivative = 0.79 \[ \int \frac {A+B x}{x^{7/2} (a+b x)^3} \, dx=\frac {-945 A b^4 x^4+525 a b^3 x^3 (-3 A+B x)-8 a^4 (3 A+5 B x)+8 a^3 b x (9 A+35 B x)+7 a^2 b^2 x^2 (-72 A+125 B x)}{60 a^5 x^{5/2} (a+b x)^2}+\frac {7 b^{3/2} (-9 A b+5 a B) \arctan \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{4 a^{11/2}} \]
[In]
[Out]
Time = 0.50 (sec) , antiderivative size = 121, normalized size of antiderivative = 0.72
method | result | size |
derivativedivides | \(-\frac {2 b^{2} \left (\frac {\left (\frac {15}{8} b^{2} A -\frac {11}{8} a b B \right ) x^{\frac {3}{2}}+\frac {a \left (17 A b -13 B a \right ) \sqrt {x}}{8}}{\left (b x +a \right )^{2}}+\frac {7 \left (9 A b -5 B a \right ) \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{8 \sqrt {a b}}\right )}{a^{5}}-\frac {2 A}{5 a^{3} x^{\frac {5}{2}}}-\frac {2 \left (-3 A b +B a \right )}{3 a^{4} x^{\frac {3}{2}}}-\frac {6 b \left (2 A b -B a \right )}{a^{5} \sqrt {x}}\) | \(121\) |
default | \(-\frac {2 b^{2} \left (\frac {\left (\frac {15}{8} b^{2} A -\frac {11}{8} a b B \right ) x^{\frac {3}{2}}+\frac {a \left (17 A b -13 B a \right ) \sqrt {x}}{8}}{\left (b x +a \right )^{2}}+\frac {7 \left (9 A b -5 B a \right ) \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{8 \sqrt {a b}}\right )}{a^{5}}-\frac {2 A}{5 a^{3} x^{\frac {5}{2}}}-\frac {2 \left (-3 A b +B a \right )}{3 a^{4} x^{\frac {3}{2}}}-\frac {6 b \left (2 A b -B a \right )}{a^{5} \sqrt {x}}\) | \(121\) |
risch | \(-\frac {2 \left (90 A \,b^{2} x^{2}-45 B a b \,x^{2}-15 a A b x +5 a^{2} B x +3 a^{2} A \right )}{15 a^{5} x^{\frac {5}{2}}}-\frac {b^{2} \left (\frac {2 \left (\frac {15}{8} b^{2} A -\frac {11}{8} a b B \right ) x^{\frac {3}{2}}+\frac {a \left (17 A b -13 B a \right ) \sqrt {x}}{4}}{\left (b x +a \right )^{2}}+\frac {7 \left (9 A b -5 B a \right ) \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 \sqrt {a b}}\right )}{a^{5}}\) | \(124\) |
[In]
[Out]
none
Time = 0.23 (sec) , antiderivative size = 437, normalized size of antiderivative = 2.59 \[ \int \frac {A+B x}{x^{7/2} (a+b x)^3} \, dx=\left [-\frac {105 \, {\left ({\left (5 \, B a b^{3} - 9 \, A b^{4}\right )} x^{5} + 2 \, {\left (5 \, B a^{2} b^{2} - 9 \, A a b^{3}\right )} x^{4} + {\left (5 \, B a^{3} b - 9 \, A a^{2} b^{2}\right )} x^{3}\right )} \sqrt {-\frac {b}{a}} \log \left (\frac {b x - 2 \, a \sqrt {x} \sqrt {-\frac {b}{a}} - a}{b x + a}\right ) + 2 \, {\left (24 \, A a^{4} - 105 \, {\left (5 \, B a b^{3} - 9 \, A b^{4}\right )} x^{4} - 175 \, {\left (5 \, B a^{2} b^{2} - 9 \, A a b^{3}\right )} x^{3} - 56 \, {\left (5 \, B a^{3} b - 9 \, A a^{2} b^{2}\right )} x^{2} + 8 \, {\left (5 \, B a^{4} - 9 \, A a^{3} b\right )} x\right )} \sqrt {x}}{120 \, {\left (a^{5} b^{2} x^{5} + 2 \, a^{6} b x^{4} + a^{7} x^{3}\right )}}, -\frac {105 \, {\left ({\left (5 \, B a b^{3} - 9 \, A b^{4}\right )} x^{5} + 2 \, {\left (5 \, B a^{2} b^{2} - 9 \, A a b^{3}\right )} x^{4} + {\left (5 \, B a^{3} b - 9 \, A a^{2} b^{2}\right )} x^{3}\right )} \sqrt {\frac {b}{a}} \arctan \left (\frac {a \sqrt {\frac {b}{a}}}{b \sqrt {x}}\right ) + {\left (24 \, A a^{4} - 105 \, {\left (5 \, B a b^{3} - 9 \, A b^{4}\right )} x^{4} - 175 \, {\left (5 \, B a^{2} b^{2} - 9 \, A a b^{3}\right )} x^{3} - 56 \, {\left (5 \, B a^{3} b - 9 \, A a^{2} b^{2}\right )} x^{2} + 8 \, {\left (5 \, B a^{4} - 9 \, A a^{3} b\right )} x\right )} \sqrt {x}}{60 \, {\left (a^{5} b^{2} x^{5} + 2 \, a^{6} b x^{4} + a^{7} x^{3}\right )}}\right ] \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 1882 vs. \(2 (163) = 326\).
Time = 109.15 (sec) , antiderivative size = 1882, normalized size of antiderivative = 11.14 \[ \int \frac {A+B x}{x^{7/2} (a+b x)^3} \, dx=\text {Too large to display} \]
[In]
[Out]
none
Time = 0.31 (sec) , antiderivative size = 154, normalized size of antiderivative = 0.91 \[ \int \frac {A+B x}{x^{7/2} (a+b x)^3} \, dx=-\frac {24 \, A a^{4} - 105 \, {\left (5 \, B a b^{3} - 9 \, A b^{4}\right )} x^{4} - 175 \, {\left (5 \, B a^{2} b^{2} - 9 \, A a b^{3}\right )} x^{3} - 56 \, {\left (5 \, B a^{3} b - 9 \, A a^{2} b^{2}\right )} x^{2} + 8 \, {\left (5 \, B a^{4} - 9 \, A a^{3} b\right )} x}{60 \, {\left (a^{5} b^{2} x^{\frac {9}{2}} + 2 \, a^{6} b x^{\frac {7}{2}} + a^{7} x^{\frac {5}{2}}\right )}} + \frac {7 \, {\left (5 \, B a b^{2} - 9 \, A b^{3}\right )} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 \, \sqrt {a b} a^{5}} \]
[In]
[Out]
none
Time = 0.29 (sec) , antiderivative size = 135, normalized size of antiderivative = 0.80 \[ \int \frac {A+B x}{x^{7/2} (a+b x)^3} \, dx=\frac {7 \, {\left (5 \, B a b^{2} - 9 \, A b^{3}\right )} \arctan \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{4 \, \sqrt {a b} a^{5}} + \frac {11 \, B a b^{3} x^{\frac {3}{2}} - 15 \, A b^{4} x^{\frac {3}{2}} + 13 \, B a^{2} b^{2} \sqrt {x} - 17 \, A a b^{3} \sqrt {x}}{4 \, {\left (b x + a\right )}^{2} a^{5}} + \frac {2 \, {\left (45 \, B a b x^{2} - 90 \, A b^{2} x^{2} - 5 \, B a^{2} x + 15 \, A a b x - 3 \, A a^{2}\right )}}{15 \, a^{5} x^{\frac {5}{2}}} \]
[In]
[Out]
Time = 0.72 (sec) , antiderivative size = 135, normalized size of antiderivative = 0.80 \[ \int \frac {A+B x}{x^{7/2} (a+b x)^3} \, dx=-\frac {\frac {2\,A}{5\,a}-\frac {2\,x\,\left (9\,A\,b-5\,B\,a\right )}{15\,a^2}+\frac {35\,b^2\,x^3\,\left (9\,A\,b-5\,B\,a\right )}{12\,a^4}+\frac {7\,b^3\,x^4\,\left (9\,A\,b-5\,B\,a\right )}{4\,a^5}+\frac {14\,b\,x^2\,\left (9\,A\,b-5\,B\,a\right )}{15\,a^3}}{a^2\,x^{5/2}+b^2\,x^{9/2}+2\,a\,b\,x^{7/2}}-\frac {7\,b^{3/2}\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {x}}{\sqrt {a}}\right )\,\left (9\,A\,b-5\,B\,a\right )}{4\,a^{11/2}} \]
[In]
[Out]